Thevenin resistance is unchanged. Given: VS = 36 V R1 = 12 kΩ R2 = 6 kΩ Solution: VTH = VR2 VR2 = VS[(R2)/(R1 + R2)] (Voltage divider formula) VR2 = 36 V[(6 kΩ)/(12 kΩ + 6 kΩ)] VR2 = 12 V RTH = [(R1R2)/(R1 + R2)] (Parallel resistance formula) RTH = [(12 kΩ)(6 kΩ)/(12 kΩ + 6 kΩ)] RTH = 4 kΩ Answer: The Thevenin voltage is unchanged, and the Thevenin resistance doubles. Given: VTH = 12 V RTH = 3 kΩ Solution: RN = RTH RN = 3 kΩ IN = VTH/RTH IN = 15 V/3 kΩ IN = 4 mA Answer: IN = 4 mA, and RN = 3 kΩ IN 4mA RN 3kΩ Norton circuit for Prob. Given: IN = 10 mA RN = 10 kΩ Solution: RN = RTH (Eq.
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1-10) RTH = 10 kΩ IN = VTH/RTH (Eq. 1-12) VTH = INRN VTH = (10 mA)(10 kΩ) VTH = 100 V Answer: RTH = 10 kΩ, and VTH = 100 V Thevenin circuit for Prob.
Given (from Prob. 1-12): VTH = 12 V RTH = 2 kΩ Solution: RN = RTH (Eq. 1-10) RN = 2 kΩ IN = VTH/RTH (Eq. 1-12) IN = 12 V/2 kΩ IN = 6 mA Answer: RN = 2 kΩ, and IN = 6 mA Norton circuit for Prob. Shorted, which would cause load resistor to be connected across the voltage source seeing all of the voltage.
R1 is open, preventing any of the voltage from reaching the load resistor. R2 is shorted, making its voltage drop zero. Since the load resistor is in parallel with R2, its voltage drop would also be zero. The battery or interconnecting wiring. RTH = 2 kΩ Solution: RMeter = 100RTH RMeter = 100(2 kΩ) RMeter = 200 kΩ Answer: The meter will not load down the circuit if the meter impedance is ≥ 200 kΩ. CRITICAL THINKING 1-23.
Given: VS = 12 V IS = 150 A Solution: RS = (VS)/(IS) RS = (12 V)/(150 A) RS = 80 mΩ 1-4 Answer: If an ideal 12 V voltage source is shorted and provides 150 A, the internal resistance is 80 mΩ. Keygen Ebp Gestion Commerciale V16 on this page. Given: VS = 10 V VL = 9 V RL = 75 Ω Solution: VS = VRS + VL (Kirchhoff’s law) VRS = VS – VL VRS = 10 V – 9 V VRS = 1 V IRS = IL = VL/RL (Ohm’s law) IRS = 9 V/75 Ω IRS = 120 mA RS = VRS/IRS (Ohm’s law) RS = 8.33 Ω RS 100RL RS >100(1 kΩ) RL >100 kΩ V = IR V = (1 mA)(100 kΩ) V = 100 V Answer: A 100 V battery in series with a 100 kΩ resistor. Given: VS = 30 V VL = 15 V RTH 1 MΩ RS.
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